Changeset - cd465118bb78
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Tom Bannink - 8 years ago 2017-03-13 13:10:40
tom.bannink@cwi.nl
Update TODO list in Mathematica notebook
1 file changed with 10 insertions and 8 deletions:
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showgraphs.m
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(* ::Package:: *)
 

	
 
Needs["ErrorBarPlots`"]
 

	
 

	
 
(* ::Section:: *)
 
(*TODO*)
 

	
 

	
 
(* ::Text:: *)
 
(*- Experimental mixing time as function of n. At (n,tau)=(1000,2.5) it seems to be between 10.000 and 20.000 steps.*)
 
(**)
 
(*- Use different starting point for switch chain that is closer to uniform:*)
 
(*   Do configuration model, starting with the vertex with highest degree and keeping track of a "forbidden list" meaning dont pair something that is not allowed*)
 
(*   (a) How close is this to uniform ? At least w.r.t. the measure of #triangles*)
 
(*   (b) How often does this procedure work/fail. Might still be faster to do switchings from Erdos-Gallai.*)
 
(**)
 
(*- Improve runtime*)
 
(*   (a) Don't remove/add edges from the std::vector. Simply replace them*)
 
(*   (b) Better direct triangle counting? (I doubt it)*)
 
(*   (b') Better triangle counting by only keeping track of CHANGES in #triangles*)
 
(*   (c) Do not choose the three permutations with 1/3 probability: choose the "staying" one with zero probability. Should still be a valid switch chain?*)
 
(**)
 
(*- Experimental mixing time as function of n. At (n,tau)=(1000,2.5) it seems to be between 10.000 and 20.000 steps.*)
 
(**)
 
(*- Count #moves that result in +-k triangles (one move could create many triangles at once!)*)
 
(**)
 
(*- Improve runtime*)
 
(*   (a) Better direct triangle counting? (I doubt it)*)
 
(*   (b) Better triangle counting by only keeping track of CHANGES in #triangles*)
 

	
 

	
 
(* ::Subsection:: *)
 
(*Done*)
 

	
 

	
 
(* ::Text:: *)
 
(*- Do a single very long run: nothing weird seems to happen with the triangle counts. Tried 10 million steps.*)
 
(**)
 
(*- Compute  Sum over i<j<k  of  (1-Exp[- d_i d_j / (2E)]) * (1 - Exp[-d_j d_k / (2E)]) * (1 - Exp[-d_k d_i / (2E)]) .*)
 
(*  Computing the f(i,j) = (1-Exp[..]) terms is fine, but then computing Sum[ f(i,j) f(j,k) f(i,k) ) ] over n^3 entries is very slow.*)
 
(*  *)
 
(*  - Improve runtime*)
 
(*   (a) Don't remove/add edges from the std::vector. Simply replace them. Done, is way faster for large n.*)
 
(*   (b) Do not choose the three permutations with 1/3 probability: choose the "staying" one with zero probability. Should still be a valid switch chain?*)
 
(*  *)
 
(*  *)
 

	
 

	
 
(* ::Section:: *)
 
(*Visualize graphs*)
 

	
 

	
 
gsraw=Import[NotebookDirectory[]<>"graphdata.m"];
 

	
 

	
 
ListPlot[gsraw[[2]],Joined->True,PlotRange->All,AxesLabel->{"Step","Triangles"}]
 

	
 

	
 
gs=Map[Graph[#,GraphLayout->"CircularEmbedding"]&,gsraw[[1]]];
 
gs2=Map[Graph[#,GraphLayout->Automatic]&,gsraw[[1]]];
 

	
 

	
 
Grid[Partition[gs,10],Frame->All]
 

	
 

	
 
(* ::Section:: *)
 
(*Plot triangle counts*)
 

	
 

	
 
(* ::Subsection:: *)
 
(*Data import and data merge*)
 

	
 

	
 
gsraw=Import[NotebookDirectory[]<>"data/graphdata_merged.m"];
 
gsraw=SortBy[gsraw,#[[1,1]]&]; (* Sort by n *)
 

	
 

	
 
gdata=GatherBy[gsraw,{#[[1,2]]&,#[[1,1]]&}];
 
(* gdata[[ tau index, n index, run index , {ntau, #tris, ds} ]] *)
 

	
 

	
 
newData=Import[NotebookDirectory[]<>"data/graphdata_3.m"];
 
mergedData=Import[NotebookDirectory[]<>"data/graphdata_merged.m"];
 
Export[NotebookDirectory[]<>"data/graphdata_merged_new.m",Join[mergedData,newData]]
 

	
 

	
 
(* ::Subsection:: *)
 
(*Plot empirical distribution of maximum degree*)
 

	
 

	
 
maxDegrees=Map[{#[[1]],Max[#[[3]]]}&,gsraw];
 
maxDegrees=GatherBy[maxDegrees,{#[[1,2]]&,#[[1,1]]&}];
 
(* maxDegrees[[ tau index, n index, run index,  ntau or dmax ]] *)
 

	
 

	
 
Histogram[maxDegrees[[1,-1,All,2]],PlotRange->{{0,2000},{0,100}},AxesLabel->{"d_max","frequency"}]
 
Histogram[maxDegrees[[2,-1,All,2]],PlotRange->{{0,2000},{0,100}},AxesLabel->{"d_max","frequency"}]
 
Histogram[maxDegrees[[3,-1,All,2]],PlotRange->{{0,2000},{0,100}},AxesLabel->{"d_max","frequency"}]
 

	
 

	
 
(* ::Subsection:: *)
 
(*Plot #trianges vs some degree-sequence-property*)
 

	
 

	
 
getProperty[ds1_]:=Module[{ds,n=Length[ds1],tmp=ConstantArray[0,{Length[ds1],Length[ds1]}]},
 
ds=N[ds1/Sqrt[N[Total[ds1]]]]; (* scale degrees by 1/Sqrt[total] *)
 
(* The next table contains unneeded entries, but its faster to have a square table for the sum *)
 
tmp=Table[1.-Exp[-ds[[i]]ds[[j]]],{i,1,n},{j,1,n}];
 
Sum[tmp[[i,j]]*tmp[[j,k]]*tmp[[i,k]],{i,3,n},{j,2,i-1},{k,1,j-1}] (* somehow i>j>k is about 60x faster than doing i<j<k !!! *)
 
(* This sparser table is slower
 
tmp=Table[1.-Exp[-ds[[i]]ds[[j]]],{i,1,n-1},{j,i+1,n}];
 
(* tmp[[a,b]] is now with  ds[[a]]*ds[[a+b]] *)
 
Sum[tmp[[i,j-i]]*tmp[[j,k-j]]*tmp[[i,k-i]],{i,1,n-2},{j,i+1,n-1},{k,j+1,n}]
 
*)
 
];
 

	
 

	
 
(* gdata[[ tau index, n index, run index , {ntau, #tris, ds} ]] *)
 
avgAndProp=ParallelMap[{getProperty[#[[3]]],Mean[#[[2,1;;-1]]]}&,gdata[[2,4,1;;100]]];
 

	
 

	
 
Show[ListPlot[avgAndProp,AxesOrigin->{0,0},AxesLabel->{"degree-sequence-property","<#triangles>"},AspectRatio->1],Plot[x,{x,1,1000}]]
 

	
 

	
 
(* ::Subsection:: *)
 
(*Plot triangle count over "time" in Markov chain instances*)
 

	
 

	
 
numPlots=20;
 
selectedData=gsraw[[-numPlots;;-1]];
 
minCount=Min[Map[Min[#[[2]]]&,selectedData]];
 
maxCount=Max[Map[Max[#[[2]]]&,selectedData]];
 
maxTime=Max[Map[Length[#[[2]]]&,selectedData]];
 
skipPts=Max[1,Round[maxTime/100]]; (* Plotting every point is slow. Plot only once per `skipPts` timesteps *)
 
coarseData=Map[#[[2,1;;-1;;skipPts]]&,selectedData];
 
labels=Map["{n,tau} = "<>ToString[#[[1]]]&,selectedData];
 
ListPlot[coarseData,Joined->True,PlotRange->{minCount,maxCount},DataRange->{0,maxTime},PlotLegends->labels]
 
(* Map[ListPlot[#,Joined->True,PlotRange\[Rule]{minCount,maxCount},DataRange\[Rule]{0,maxTime}]&,coarseData] *)
 

	
 

	
 
(* ::Subsection:: *)
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