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Location: CSY/reowolf/testdata/parser/positive/8.pdl

Christopher Esterhuyse
more logging, testing, examples and bugfixes: (1) components remember whether they have submitted a solution; only those are considered when selecting a branch at the end of a round, (2) retrying active connections during setup phase were using the wrong index for looking up their TODO structure, (3) recently failed connections are deregistered from mio and reregistered after the retry process restarts s.t. they don't produce a storm of mio events
#version 100

/*
Suggested by Luc Edixhoven.
Source: https://en.wikipedia.org/wiki/Thue%E2%80%93Morse_sequence

In mathematics, the Thue–Morse sequence, or Prouhet–Thue–Morse sequence,
is the binary sequence (an infinite sequence of 0s and 1s) obtained by
starting with 0 and successively appending the Boolean complement of the
sequence obtained thus far.

To compute the nth element t_n, write the number n in binary. If the
number of ones in this binary expansion is odd then t_n = 1, if even
then t_n = 0. For this reason John H. Conway et al. call numbers n
satisfying t_n = 1 odious (for odd) numbers and numbers for which
t_n = 0 evil (for even) numbers. In other words, t_n = 0 if n is
an evil number and t_n = 1 if n is an odious number.

*/

import std.reo;

composite main(out x) {
	channel ao -> ai;
	channel bo -> bi;
	channel co -> ci;
	new evil_or_odious(ai, bo);
	new replicator(bi, {co, x});
	new recorder(ao, ci);
}

primitive evil_or_odious(in x, out y) {
	while (true) {
		synchronous {
			if (fires(x) && fires(y)) {
				msg a = get(x);
				msg result = create(1);
				boolean even = true;
				int i = 0;
				while (i < a.length) {
					if (a[i++] == '1')
						even = !even;
				}
				result[0] = even ? '1' : '0';
				put(y, result);
			} else {
				assert !fires(x);
				assert !fires(y);
			}
		}
	}
}
primitive recorder(out h, in a) {
	msg c = create(0);
	while (true) {
		synchronous {
			if (fires(h) && fires(a)) {
				put(h, c);
				{
					msg x = get(a);
					msg n = create(c.length + 1);
					int i = 0;
					while (i < c.length) {
						n[i] = c[i];
						i++;
					}
					n[c.length] = x[0];
					c = n;
				}
			}
		}
	}
}